If I calculate F3 using: (F3 = Fb*((1/Qtc^2-2+((1/Qtc^2-2)^2+4)^0.5)/2)^0.5)
and then put that frequency in to: (dBmag = 10*LOG(Fr^2/((Fr-1)^2+Fr/Qtc^2)))
dBmag does not = -3. Why?
Seems when I compare graphs made by CAD applications (for sealed boxes) the graphs are tend to be much "louder" than what the dBMag formula above tends to predict.
