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Date: December 26, 2002 at 11:13:03
From: Brian Owens, [kottke-web.paccar.com]
Subject: Correct me if I am wrong. . . .

URL: my webpage. . .


But, by the formula on this website,

Lv = (23562.5*Dv^2*Np/(Fb^2*Vb))-(k*Dv)

Np is number of ports, and Vb is box volume. So, double the box volume, and double the number of ports, and Lv should be the same.

Double the box volume for the second sub, and just double the number of ports the same diameter and length.

Brian


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