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Date: March 28, 2002 at 11:18:33
From: Brian Owens, [newhq.paccar.com]
Subject: Re: Hey Adrian

URL: My Webpage. . .


you are correct, that is 1 ohm, but the power to each driver will not be the same.

See if you follow me here:

What you have wire is:

(2) 4 ohm in series // in parallel with:
(2) 4 ohm in series // in parallel with:
(1) 4 ohm // in parallel with:
(1) 4 ohm // in parallel with:
(1) 4 ohm


That is a 1 ohm load. Let's assume we drive 100 watts to this load. P=i^2 * R P=100, R=1, then i=10 amps.

Let's take the equivalent circuit for just the 4 drivers wired in series/parallel. The equivalent of these 4 drivers (resistive wise) is a single 4 ohm driver. . .follow me? If that is the case, then we could redraw the circuit as (4) 4 ohm drivers in parallel, so the current through each driver is 2.5 amps. P=2.5^2 * 4 = 25 watts each

Now comes the problem. One of our 4 ohm resistors in our 'redrawn' circuit is actually (4) 4 ohm subs, right? Guess what. . .Those 4 subs combined together get the same amount of power as each of the other 3 subs. . . .6.25 watts each!!!!


You can also look at this with circuit analysis and see that you have 5 parallel cicuits wiring this way. 3 of the branches are 4 ohms, and 2 of them are 8 ohms. If you look at the example of 100 watts, you get 2.5 amps through each of the 4 ohm branches, and 1.25 amps through the 8 ohm branches. Using p=i^2 * R, you get 25 watts to each of the 4 ohm branches, and 6.25 watts to each sub in the 8 ohm branches.

Anything you are confused on, let me know.

Brian


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