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Date: March 28, 2002 at 10:48:10
From: Adrian Mack, [wtpp-p-203-54-83-78.prem.tmns.net.au]
Subject: Re: Hey Adrian |
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Now I'm not sure if this is going to give equal power to all drivers... but this what I came up with for 7 drivers to get a 1 ohm load:
*2 drivers wire in series to 8 ohms
*Another 2 drivers wire in series to 8 ohms
*Ok so now their are two sets of 8 ohms. Wire those in paralel to get 4 ohms.
*Wire a single 4 ohm driver in paralel with the above 4 ohm load to get 2 ohms
*Wire 2 drivers in parallel to get 2 ohms, and then wire this in parallel with the above 2 ohm load to get 1 ohm load.
Ok I dont know if I wrote the above in a way that made sense, so:
d=driver
*=wire in series
/=wire in parallel
2d*4=8 }
} Wire these in paralel to get 4 ohms
2d*4=8 }
1d*4=4 } Wire this 4 ohm driver in parallel to the above to get 2 ohm load
2d/4=2 } Wire this 2 ohm load to the above 2 ohm load in parallel to get 1 ohm load
=1 ohm load
What do you think Brian? Does it look like power would be spread equally? I dont have enough time to figure it out. I would like to know if anyone sees anything wrong with the above!
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Posted with TalkShop version
2.73 - BETA |
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